wait til math-illiterate niggers takeover thread claiming it's 50%
Wait til math-illiterate niggers takeover thread claiming it's 50%
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It is 50.
Its either the left, or mid box.
1 ball has already been removed. 1 ball left
Its either red, or green. 50%
Hey OP, do i know you?
i've made this thread many times with golden and silver balls.
2/15ths dumb cunts
i came back here this year and was posting til 2017, definitely don't remember this shit with any color
how the fuck did you get the 15?
33%
I’m a big brainer
really?
i've used this picture to make this thread like 30 times total, pretty much always the same result, most people get it wrong.
You're all idiots. There will be a possible of 5 balls left. 2 out of those 5 balls are green. Therefore the odds are 2 out of 5 possible outcomes. 2/5 x 100 = 40%
This.
explain how the fuck is 40%.
If I pick a green ball it sure is not from the box with 2 red balls in it.
Either Box A or Box B. 50-50 to pick up the second green one of box A, or the red one of box B
Oh shit nvm. This is wrong. I'm the idiot. Ok ok wait. If you took out a green one then you either have the left box or the middle box. Therefore there are only 2 possible options. Wtf it is 50%. Am I wrong? It feels right. Wtf kind of troll is this. Is the troll that it IS 50% and we're made to doubt. Or is that troll that it isn't 50% and we're all idiots. WTF!
>most people get it wrong.
cause they dumb
Yea you're right. I fucked up. I have corrected myself in this reply.
Conditional probability doesn't make you look smart, it makes you look fucking retarded.
the troll is that its not 50%, conditional probability is very counter intuitive, this problem is probably older than you and its fucks with people like your mother.
I went shopping the other day and the lady at the counter was super helpful. I think she was flirting with me. Anyway she said "If you need anything, I'm Jill." And I was like "Wow...I've never met a woman before...with a conditional identity! What if I don't need anything! Who are you?!" "If you don't need anything I'm Eugene."
P(Box1|G) =
(P(G|Box1)*P(Box1)/P(G) =
(1*0.33) / 0.5 =
0.66
Bayes Theorem, faggots
Basically it's 1 out of the 3 green balls and 2 of em are in the first box, so 60%?
thread
nice bait. it is 50% because this is more logical than mathematical. If ball1 is green , then box(red+red) is eliminated entirely. remains only (green+red) and (green+green). extract the green ball and the options are (red) and (green). The chances for either of these is 50%
No math is even needed for this, if you pull out a green ball you have equal chance of pulling a red or green ball out of the same box.
The all red box is out of the equation because you pulled a green ball.
You have a 50% chance of pulling either color, it's really simple and there isn't any need to over-complicate such a pointless problem.
This isn't how probability works, retards.
rofl, look at these brainlets.
i guarantee that
>nobody likes you
and
>in an irl situation you would prove us right
i guarantee that
>nobody likes a brainlet
and
>what a faggot you are
33%
You don't ignore what you already did, otherwise it would be 50%
In a thread i made wih this exact topic a science Yas Forumsro made a physical test, he did this 100 times and concluded that the answer is NOT 50%.
(im not gonna tell you what it is, figure it out yourself)
>LOL NOBODY LIKES PEOPLE THAT AREN'T RETARDED
cope
Uhh, what? Sorry, I don't speak retard.
If you get a green ball then it must be one of the 3 green balls. If it's one of the first 2 then the other ball is green. If it's the third then the other ball is red. Thus, 66%, faggot.