Wait til math-illiterate niggers takeover thread claiming it's 50%

wait til math-illiterate niggers takeover thread claiming it's 50%

Attached: pl.png (1024x768, 49.53K)

Other urls found in this thread:

en.m.wikipedia.org/wiki/Bertrand_paradox_(probability)
twitter.com/SFWRedditImages

It is 50.

Its either the left, or mid box.

1 ball has already been removed. 1 ball left

Its either red, or green. 50%

Hey OP, do i know you?
i've made this thread many times with golden and silver balls.

2/15ths dumb cunts

i came back here this year and was posting til 2017, definitely don't remember this shit with any color

how the fuck did you get the 15?

33%
I’m a big brainer

really?
i've used this picture to make this thread like 30 times total, pretty much always the same result, most people get it wrong.

Attached: balls.jpg (320x269, 30.49K)

You're all idiots. There will be a possible of 5 balls left. 2 out of those 5 balls are green. Therefore the odds are 2 out of 5 possible outcomes. 2/5 x 100 = 40%

This.

explain how the fuck is 40%.
If I pick a green ball it sure is not from the box with 2 red balls in it.
Either Box A or Box B. 50-50 to pick up the second green one of box A, or the red one of box B

Oh shit nvm. This is wrong. I'm the idiot. Ok ok wait. If you took out a green one then you either have the left box or the middle box. Therefore there are only 2 possible options. Wtf it is 50%. Am I wrong? It feels right. Wtf kind of troll is this. Is the troll that it IS 50% and we're made to doubt. Or is that troll that it isn't 50% and we're all idiots. WTF!

>most people get it wrong.
cause they dumb

Yea you're right. I fucked up. I have corrected myself in this reply.

Conditional probability doesn't make you look smart, it makes you look fucking retarded.

Attached: agane.jpg (604x647, 28.55K)

the troll is that its not 50%, conditional probability is very counter intuitive, this problem is probably older than you and its fucks with people like your mother.

I went shopping the other day and the lady at the counter was super helpful. I think she was flirting with me. Anyway she said "If you need anything, I'm Jill." And I was like "Wow...I've never met a woman before...with a conditional identity! What if I don't need anything! Who are you?!" "If you don't need anything I'm Eugene."

P(Box1|G) =

(P(G|Box1)*P(Box1)/P(G) =

(1*0.33) / 0.5 =

0.66

Bayes Theorem, faggots

Basically it's 1 out of the 3 green balls and 2 of em are in the first box, so 60%?

thread

Attached: juxxxx.jpg (3715x2991, 1.85M)

nice bait. it is 50% because this is more logical than mathematical. If ball1 is green , then box(red+red) is eliminated entirely. remains only (green+red) and (green+green). extract the green ball and the options are (red) and (green). The chances for either of these is 50%

en.m.wikipedia.org/wiki/Bertrand_paradox_(probability)

/thread

No math is even needed for this, if you pull out a green ball you have equal chance of pulling a red or green ball out of the same box.

The all red box is out of the equation because you pulled a green ball.

You have a 50% chance of pulling either color, it's really simple and there isn't any need to over-complicate such a pointless problem.

This isn't how probability works, retards.

rofl, look at these brainlets.

i guarantee that
>nobody likes you
and
>in an irl situation you would prove us right

i guarantee that
>nobody likes a brainlet
and
>what a faggot you are

33%
You don't ignore what you already did, otherwise it would be 50%

In a thread i made wih this exact topic a science Yas Forumsro made a physical test, he did this 100 times and concluded that the answer is NOT 50%.
(im not gonna tell you what it is, figure it out yourself)

>LOL NOBODY LIKES PEOPLE THAT AREN'T RETARDED
cope

Uhh, what? Sorry, I don't speak retard.

If you get a green ball then it must be one of the 3 green balls. If it's one of the first 2 then the other ball is green. If it's the third then the other ball is red. Thus, 66%, faggot.