>player opens 2 out of 3 doors
>"50% probability he finds his car"
lolwut
How smart are you, Yas Forums?
Leo Wood
Juan Brown
he either finds it or doesn't find it
basic probability you dumbass
Jaxson Evans
they should all open different combinations of doors than each other, and they'll have a 1/3 chance of winning
because there are 6 different possible arrangements for the cars, and 4 possible ways to lose
Bentley Walker
The odds are 2 to 1 in favor. Because the ones who find their car honk the horn while they wait. So as long as the first guy finds his everyone wins.
Xavier Sanders
That's not how probability works. 3 options two choices. Odds are 2/3 that's 66%. Way to prove your own ignorance.
Camden Bell
Unfavorable outcomes are 2x2x2 or 8
Favorable outcomes are 1
So chance is 1/8
Jaxson Myers
well everyone has 2/3 chance. I was gonna say if Robert Throws it and doesn't get it right then the doors would stay open.
"What is the winning probability if all players act optimally?" Their own probability or the groups?
If they were smart they wouldn't all Nix the same door so I'd say that should up their probabilty
Eli Ward
no
it's as follows:
- probability of the correct car being in the first door: 1/3
- probability of the correct car being in the second door: 1/3
now that's 2/3, but you have to multiply by 2/3 which is the probability of the car not being in the third door, that gives you 4/9, ok not exactly 50% but i rounded it, doesn't matter
Wyatt Torres
to add to this, it's the same odds for two players to open the same doors as each other, as long as the remaining third player opens the door that they didn't. So the only way to fuck up the game is if they all open the same two doors, in which case their chance of winning is 0
Dominic Green
If you want to go that route the first draw is 1/3 but there's one two doors left for the second draw so that would be 1/2. You really shouldn't go that far into detail if you don't understand the subject.