How smart are you, Yas Forums?
How smart are you, Yas Forums?
Henry Ross
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John Rogers
First guy opens door 1,2, 50% probability he finds is car
Second guy opens door 1 and 3 again, now 25% probability he finds his
Third guys opens the last combination 2, 3, now 12.5% probability (again you remove one possible place so halve the probability)
So 50 + 25 + 12.5 = 77.5% probability
Ethan Cooper
your puzzle sucked op
William Ramirez
I lost
Grayson Bailey
I am very smart. Rob Billy and Bob all fuck eachother and shoot the show host and steal the cars and drive away, and then go to a hotel and have a threesome again
Samuel Thompson
This doesn't even make sense.
Henry Roberts
lol why not? just because you don't understand it doesn't mean it doesn't make sense. Try to read it again and give it a thought, you'll see I'm right.
Colton Morris
Why would the probability of finding the correct car be reduced for the next player? Everything is "reset" between each player making their picks.
Josiah Martin
if the first guy didn't find his car, then the second cannot find his. but if the first guy found it, then the second can find it as if it were reset. 50 * 0 (first guy doesn't find it) plus 50 * 50 (first guy finds it) = 25%
John Anderson
This sounds like a scaled-down version of the 100 prisoner problem. I'd say that what you'd do is to give them all numbers. So red is 1, green is 2, and blue is 3. Then when they start, what they should do is open their door. If it's the right one, they're set. If it isn't, they should open the door of the corresponding color. So for this example red should open the first door, with the blue car. Since it wasn't red, red should then open the 3rd door, since blue is 3. If you do that, I think there's a 2/3 chance of winning in total.
If you blindly pick, each person has a 2/3 chance of getting their car. But all 3 need to do that, so it's really an 8/27 chance of them all getting it.