How smart is Yas Forums?

my brain hurts

According to your own reasoning it's 66% retard

Okay, you know you have either green-red or green-green by virtue of the fact that you pulled a green ball out of your box. (You couldn't have pulled a green ball out of red-red)
Possibility #1: you had green-green. Then the other ball is green.
Possibility #2: you had green-red. Then the other ball is red.
One of the two possibilities is that the other ball is green. 1 in 2 = 50%

That would be true, except i dont think we count that since its already guaranteed we have a green ball in our hand, if we got a red ball we just pick again

Don't waste dub dubs on stupid shit.

that would be on first draw with no red box only.

the other is a 50% chance its green, and a 50% higher probability its the green box because you drew green first, thus giving the 50% another 50% equaling 75%

i think people are mixing up possibility and probability. you need to include the data from the odds of drawing green the first time into the equation.

It simply doesn't matter.

Do I care if I get a red or green ball?

Do I care if I guess and I'm wrong?

Why would I even play your game OP, does it make you cum if someone gets the answer wrong? Are you some kind if nerd sadist?

I refuse to even think about it, I have better shit to do, enjoy your nerd games.

>takes all the balls and slams the door.

We used to be friends OP.

2/3
Nowhere does it say you were guaranteed to pick a green ball from the box. The question is "what is P(2nd green | 1st green)". Half the time you pick the one with 1 green and 1 red you pick the red one first, whereas 100% of the time you pick the 2 green one you pick a green ball first. It is twice as likely that, if you picked a green ball first, it was the box with 2 green balls, and so the second ball will be green too.

75%

That's irrelevant by virtue of the setup and the question originally posed. You have three boxes:

[GG] [GR] [RR]

You select a box, pull a 'G'.

What is the probability of the other ball from the same box being a 'G'?

You know there's a [RR] box, so that's discounted outright. The box you have in your hand, then, will either contain one additional 'G' or one 'R'. Those are the only possible outcomes, making the probability 1/2, or 50%.