How smart is Yas Forums?

2/3 because if you picked a green ball odds are it was from the box with two green balls

but you already took one of those green. So it's 50%

You don't know which box you have. You have to take the average chances between the 2 green and 1 green, 1 red boxes. The chances that you reach in and get a green ball is 2/3 because there are three potential balls left, with two of them being green.

75%

50% green and 50% red
you picked a green ball
the odds the next is green is 50%
the only boxes you have with green are the first 2 and you have a green. the means the only other options is could be one red or one green within that SAME box you drew from. but you have to figure you have a 100% chance of it being green in the green box and 50% chance of it being green if you chose the mix box. meaning if you took a green out of the box you have 50% more odds to be drawing from the green box and giving you a 75% probability that the other ball is green in that box.

now it would be 66% chance if you took away the red box and asked what is the odds of drawing a green ball. but thats not the case.

this

correct

50/50 you are either gonna get a green or a red only possible combination.

50%
You know its not the red red box, cause you already have a green. So now its either you choose a red or a green. 50/50
Come the fuck on guys

You cant categorize it as two separate green balls, the box with two green balls becomes the same outcome and reduces probability down to 50%.

but what are the odd of drawing a red from another box? and what are the odds the 2nd ball in the first on would be green after the red from another were drawn?

my brain hurts

According to your own reasoning it's 66% retard

Okay, you know you have either green-red or green-green by virtue of the fact that you pulled a green ball out of your box. (You couldn't have pulled a green ball out of red-red)
Possibility #1: you had green-green. Then the other ball is green.
Possibility #2: you had green-red. Then the other ball is red.
One of the two possibilities is that the other ball is green. 1 in 2 = 50%

That would be true, except i dont think we count that since its already guaranteed we have a green ball in our hand, if we got a red ball we just pick again

Don't waste dub dubs on stupid shit.

that would be on first draw with no red box only.

the other is a 50% chance its green, and a 50% higher probability its the green box because you drew green first, thus giving the 50% another 50% equaling 75%

i think people are mixing up possibility and probability. you need to include the data from the odds of drawing green the first time into the equation.

It simply doesn't matter.

Do I care if I get a red or green ball?

Do I care if I guess and I'm wrong?

Why would I even play your game OP, does it make you cum if someone gets the answer wrong? Are you some kind if nerd sadist?

I refuse to even think about it, I have better shit to do, enjoy your nerd games.

>takes all the balls and slams the door.

We used to be friends OP.

2/3
Nowhere does it say you were guaranteed to pick a green ball from the box. The question is "what is P(2nd green | 1st green)". Half the time you pick the one with 1 green and 1 red you pick the red one first, whereas 100% of the time you pick the 2 green one you pick a green ball first. It is twice as likely that, if you picked a green ball first, it was the box with 2 green balls, and so the second ball will be green too.

75%

That's irrelevant by virtue of the setup and the question originally posed. You have three boxes:

[GG] [GR] [RR]

You select a box, pull a 'G'.

What is the probability of the other ball from the same box being a 'G'?

You know there's a [RR] box, so that's discounted outright. The box you have in your hand, then, will either contain one additional 'G' or one 'R'. Those are the only possible outcomes, making the probability 1/2, or 50%.

Holy fuck you are stupid. You don't "give the 50% another 50%". What you're saying is that the chance of picking a green ball from the green box is 100%, whereas picking a green ball from the mix box is 50%. That comes out to a ratio of 2:1 or a 2 out of 3 chance you picked the green box.

Alright so you pick a random box and pull out a green ball. Now you could've either picked a box with 2 green balls or 1 green and 1 red. However since the odds of you pulling out a green ball of the 1 green 1 red box is 50% that lowers the odds of you picking that box. So I guess I would say 2/3? Am I right or wrong?

This is a revamped Monty Hall problem

Read this: