Should voting come with an IQ test?
>pic related
>if you can't get the right answer, you can't vote
Should voting come with an IQ test?
>pic related
>if you can't get the right answer, you can't vote
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holy shit 90% of the planet wouldn't be able to vote. sounds good to me though. let me finish eating this crayon first....
98
109
32
yes it should
73 dickheads
Bingo
looks like some retarded niggers can't notice the last witch doesn't hold nor broomstick nor magic rod
15+4x7=109
73
this thread is scaring. Too much stupidity
Depends on where you put the parentheses.
x + (y * z) = 43
(x + y) * z = 88
TLDR replies...
Dumb wizzard bitch is worth a broom.
Fuck you, yeah you're right. I put 109 thinking that the stupid cunt had her little wand and broom.
The answer is 73 you fucking apes
Just take a goddamn hard look at the pic. The bitch isn't holding anything in the bottom row so subtract that value first. AND THERE ARE 2 WANDS IN THE LAST LINE...
3+5x14 = 73...
the trick with these post is that one of the variables images in this case the first is a deferring value then it is in the final equation. The first image is composed of the witch the wand and the broom. In the final equation the witch isn't holding either of those objects and so is not worth the same as in the first case
5?
LOL no, it's 32 you fucking ape.
15+15+15=45
7+7+7=21
4+4+4=12
4+15*7= 4+105 = 109
please return to masturbating
No, there is no parentheses, there is no need, multiplying just has priority.
4 brooms shown in second line, so each is 3
This
Wand = 7
Broom = 3 (There's 4 brooms)
Wizard = 5
3+(5*14) = 73
Yeah. Minus the broom and minus a wand. So 15 - 7 for the wand and 3 for the broom makes 5.
Look at the hands of the wizard
And notice that some brooms/wands are double.
Math right, but OP is a fuckhead, bitch has both broom and want in her hand 45=3bitch+3wand+3broom
It is too much to assume that it is intentional instead of a graphical error unless specifically mentioned. Pixel by pixel none of the like images are exactly the same.
The only correct answer
38
>he thinks the popular vote amounts to anything
it's pretty obvious it's a double broom/ double wand, not a "graphical error". That's the trick with these things. don't get aggro cause you didn't notice.
Wrong look closer
This picture is too blurry
Answer to end it all:
3witch+3wand+3broom=45
3wand=21
4broom (one is double)=12
broom+witch*2wand (this is a double too)=X
solve:
wand=7
broom=3
3witch+3*(7+3)=45
witch=5
broom+witch*2*wand=3+5*2*7=73
forgot to show working out which was 15 for girl wand and broom
broom is 3
wand is 7
means girl is 5
5(girl)x7(wand)+3(broom)
38
73
(7+5+3)+(7+5+3)+(7+5+3)=45
7+7+7=21
3+(3+3)+3=12
3+5*(7+7)=73
123
broom is 3
wand is 7
girl is 5
5(girl)x14(2 wands worth 7 each)+3(broom)
123
Girl is 15, wand is 7 and broom is 4, so girl (15) x wand (7) is 105 plus broom (4) is 107 because of bidmas
The riddle is supposed to be hard, because there are small tricks hidden inside, like twice the same objects, between others, but OP is a faggot who cant HD, so solving this one is impossible.
3 wands = 21
Wand = 7
4 brooms = 12
broom = 3
3 x Witch with broom and wand = 45
Witch with broom and wand = 15
Take off the broom (3) and the wand (7)
Witch alone = 5
Broom + Witch * 2 wands
3 + 5 * 2 * 7 =
3 + 70 =
73
Thanks anons. Now I know my value as a woman.
5
Where the fuck do you see a 4th broom? Thanks for publicly outing yourself as a blind retard though
Witch=15
Wand=7
Broomstick=4
(4+15)×7= 133
> 4 brooms
Brah
Just noticed the witch is holding a broomstick and a wand
32. Witch isn't holding the broom or wand. Shit tier "iq test" though
How do we know that the wand and broom merely add to the power of the witch, and do not in fact vastly multiply her power, especially when used in combination?
73, all other answers are from brainlets.
Maybe the witch is really worth 0, and the combined power of a wand and broom equals 15 despite them being worth only 7 and 3 individually. There is a 50% bonus to their overall power when dual-wielded. The witch actually just functions as a catalyst/conduit through which the power of a wand and broom can be combined and enhanced.
Okay, since you retards can't do elementary math, I'll just spoonfeed it to you.
>The wand = 21/3 = 7
>The broom = 12/4 = 3
>The witch has 1 of each, so (45 - ((7*3)+(3*3)))/3 = (45 -30)/3 = 15/3 =5
>Finally, broom + (witch * 2 wands) = 3 + (5*2*7) = 3 + 70 =73.
The answer is 73 you room-temperature IQ niggers.
Here's an illustration of item count.
No. But welfare recipients and felons should not ve allowed to vote.
Actually it's one. The outfit is 4/5 of the value
Math fag here. The answer is 19.
Witch =15
not 5
now something hard