??? Help

??? Help

Attached: FB_IMG_1586376441940.jpg (745x960, 40.32K)

73

impossible since witch is 15 and star is 7, which means that ? is more than 100

who cares

Hurrr

109

73.

84

Indeed 109

impossible since witch is 15 and star is 7 which means that ? is more than 100

20

Witch is 5.

Each of the witches of the 1st. line have a wand (7) and broom (3) with them, but the witch of the 3rd. line doesn't.

32

3x+3y+3z=45
3y=21
4z=12

x+2y+z=??

y=21/3 = 7
z=12/4 = 3
x=(45-(3*7)-(3*3))/3 = 5

3+(5*7*2) = 73

THE ANSWER IS NIGGER, YOU HEAR ME?!

witch = 15
witch isnt holding broom or star so minus 7 from 15.
3+8x7+84

Yep

Oh boy, here we go agin with this shitty thread

3 times witch, plus 3 times wand, plus 3 times broom is 45, so 1 witch + 1 wand + 1 broom is 15.

3 times wand is 21, so 1 wand is 7

3 times broom is 12, so 1 broom is 4

Remember the first part? We have 2 of the 3 values now.
Witch + 7 + 4 = 15
Witch = 15 - 7 - 4
Witch = 4

And for the last one, since you do multiplication first, 4 + 4 x 7 = 32

There, thread's over. Go fap to traps or whatever

Witch is

Witch is 4 you fucking idiot

No. Fuck you.

idiot, 4 brooms = 12
broom = 3

also, its two wands in last equation.

woah i am outsmarted
didnt enhance op image because these threads usually suck so didnt see it

You're right, I didn't see that.

But since you need to call other people idiots, fuck you

Wand = 7
Broom = 3 (there are two brooms in the middle)
Witch with Broom and Wand = 15
Witch minus Broom (3) and Wand (7) = 5

Broom 3 + Witch (5) x two Wands (14)

3 + (5x14) = 210

154
3 witches with broom and star = 45 (15)
3 stars = 21 (7)
4 brooms = 12 (3)
1 broom + 1 witch with nothing x 2 stars 3+8x14=154

Wicked samefagging

x+x+x = 45
>3x=45
x=15
y+y+y = 21
>3y=21
y=7
z+z+z = 12
>3z=12
z=4

z+(x-y-z)*y=?
4+(15-7-4)*7=?
4+(4)*7=?
4+28=?

32=?
Answer is 32

Where'd you get 8 from?!

Answer 32
everyone else is a retard
Post witches now

Attached: EUwpv8pUwAMgu3-.jpg (1344x1976, 341.76K)

the amount of countries the jews have be expelled from

Put your glasses on, its 32 faggots

Unknown due to undefined characters in lower string.
These stupid questions are intended to get posts by creating arguments.
Fuck off and die already.

It's actually

X+X+X = 45
Y+Y+Y = 21

Z+2Z+Z=12

Z+(X-Y-Z)x2Y = ?

No.. there are two wands in the last equation.. i.e.

1br (3) + (1 witch (5) x 2 brooms (14))

3+(5x14) =

73

fucked it up. So the answer is now 112
the witch with nothing is 5. So 3+5x14=112

so every broom is 3, every wand is 7, which means that every witch must be 5
this concludes that ? = 3 + 5 x 14 =73 indeed

Attached: 1562257987371.png (240x268, 116.41K)

60 4+4*14 (2 wands)

>5 x 14 = 109
intradesting user

32. Everyone else is decidedly wrong

only if you can't see the second wand in the last equation...

Didn't see the 2 brooms so 73 is correct

Ya I now see it so it is 60

4+4*14

>now some witch time

Attached: illust_73320519_20191110_053406.png (1067x1200, 1.27M)

considering the bullshit 3+(5x14)=73
fuck math and fuck you.

no thing in the entire equation is 4

thats not bullshit, thats just math, we had 1438901284 threads discussing this issue already

15

Ya this whole thing just fuck my ass with simple ass tricks

I couldn’t :(

that's the point, OP wants to fucking annoy us, we're an anthill and the picture is his stick

Is it not 15? Wand 7. Broom 4 and witch 4.

Shot. I missed the X. 32.

still wrong since there is a double broom and a double wand and op has a huge dildo up his asshole

109

26.84205310871674665830

32

He needs a better quality pic if he's going to pull that shut.

Bingo

This

56

3(Witch) = 45
Witch = 45/3 = 15

3(Wand) = 21
Wand = 21/3 = 7

3(Broom) = 12
Broom = 12/3 = 4

Broom+(Witch*Wand) =
4 + (15*7) =
4 + 105 =
109

32

15 + 15 + 15 = 45
7 + 7 + 7 = 21
3 + (2 * 3) + 3 = 12 >one double broom

3 + (15 - 7 - 3) * (2 x 7) = ? >no wand, no broom on wich * 2 wands
3 + 5 * 14 = 73

Absolute dogshit image quality

Attached: fdgkjnfnkrtnkefdlkvc.png (1033x237, 228.63K)

so....we arent done with the retarded ass math question and no goig to post witches?

Attached: ++++1539802222699.jpg (980x1180, 142.96K)

You retarded monkeys don't know anything.

You have a system of 4 equations but there are 5 unknowns, so there is no unique solution.

Fuck this gay shit.

1 wand + 1 wand + 1 wand = 21.
1 wand = 7.

1 broom + 1 broom + 1broom = 12.
1 broom = 4.

1 witch holding both a broom and a wand + etc. + etc. = 45.
3 wands = 21 + 3 brooms = 12 = 33.

45 - 33 = 12.

1 witch + 1 witch + 1 witch = 12.
1 witch = 4.


1 broom + 1 witch x 2 wands = ?

4 + 4 x 14 = ?

4 + 56 = ?

60 = ?

Think I mistyped in the calculator before. it's 73

Motherfucker, there is 2 brooms in the middle. Christ.

There 2 broom and 2 wands

so it 1 broom + 2 brooms + 1 broom = 12.
1 broom = 3.
.

I just realized

3 + 5 x 14.

3 + 70.

so 73.

Fuck.

Attached: DrmQvnQX4AAI5zV.jpg (1024x768, 93.45K)