>0.9999... * 10 = 9.9999... || -0.9999...
>0.9999... * 9 = 9 || /9
>0.9999... = 1
Well?
X=0.9... /*10
10X=9.999...
-
9X=9 /9
X=1
No. It's always less than one, however infinitesimally small. It will never be one, and therefore cannot be one.
Two numers are identical when there is no third number between them.
So yes, 0.9999... = 1
Easy proof.
0.999999... x 10 = 9.9999999...
9.99999... - 0.999999 = 9
So 10 x 0.99999999... - 1 x 0.999999999... = 9
9 x 0.99999999... = 9
0.999999... = 1
To imply that repeating digits of 9 at the end will always have a 1 at the last decimal place of its difference when subtracted from one
>infinitesimally small
Correct
However math tends to simplify this for mainstream consumption so they don't have to process irrationals and deal with infinity
There is a number between them
1/inf
Wrong
Thought only /sci/fags were discussing this shit.