This should be easy

Can you please show work before thread dies

2/3, you know you don't have the third box as soon as you get a gold coin.

1/9

I've done this thread before, but because the problem is kinda old, its not that well known outside of math classes on conditional probability, but just an hour ago a video was posted that explains it very well.

So i will post a link to it a little later.

50% likelihood it's gold

2/3 because there's 2 gold balls and one silver remaining after excluding the silver silver box

They are right and you suck.

You have box A or box B, so changes that you pick a second gold ball is 50%
Now if we did not know the first ball and your question was how big the changes are of picking two gold balls, the answer would be 25%

That would only be right if all balls were in one box, which they are not.

they are wrong and you suck.
you have no idea what you are talking about but you still act like you do.
i KNOW the answer, i know every aspect of it, even the name of the person that came up with it and when he came up with it.

I will post evidence a little later.

60% chance you get a silver ball