Alright Yas Forums... time for a brainlet test

Count increases by one in each diagonal. Color pattern in 2 white 1 black. Position rotates by number of previous count.

3.

Pattern:
Only 1 black per row/column.
+1 to dots per colum down/row to right
Dot position rotates counterclockwise by as many times as there are dots

It's obvious. It only jumps across when the number of dots is even. The number is even, therefore, it's 1.

I thought it was 4 too. But it has to be black in this case becase of surrounding pattern. So 2.

2
Every pattern has 2 of the same and 1 that isn't.
Every square only has one section with shapes in it, therefore any square with multiple shape-sections are automatically ruled out

this seems right

Why do you think the next sequence has to be black?

its 4, theyre grouped by threes. If you assign them numbers from 1-9 left to right up to down (3,5,7) are together, (1,6,8), and 9, which we need is grouped with 2 and 4. The dots on 3 matched squares add up to 9, and have the same color. The numbers should be on the opposite side like with (1,6,8) hence 4

Germanbro is correct.

>Top to down
>left to right
>1, 2 ,3
>2,3,4
>3,4,?
What could it be? What is the pattern? How many dots will there be? Where will the place the dot's will be?

Can you give us something harder?
I would say it's 1, but I am not sure if the dot's being filled or not matters. The answear is 5 dot's for sure, so 5 and 6 is going away, then you have the case of dot's being filled or not. Normally it would be 1 because the pattern of up left right down would repeat, but then you have the filling of the dot's that is probably irrelevant.

So my answear is 1

This one also makes sense.

nevermind, is correct

Yeah I think this.. rotate 4 times and change to white.. pretty awful

1 rotate counter clockwise change to white and get 2

2 rotate counter clockwise twice and stay white leading to position 3

3 rotate 3 quadrants counter clockwise and turn black leading to 4

4 rotate 4 quadrants and change to white

and there ya go.. if each quadrant had a defined color I think it would be a more clear solution that would make the solution better defined

so far as I can tell it is either black white white black white white (for no apparent reason) or the problem is semi-inconsistent

this is either poorly worked out by me or (almost as usual) kind of a troll

if the quadrants had a color definitely set to it. it would make more sense. there is no 5 black dots South quadrant.. Im going to say this problem is poorly realized in terms of a self-evident and consistent logic

3/10

So why is the third sequence not counter clockwise from the 2nd

The answer will be given and the brainlets will be roped after the thread passed 50 replies.

Three white dots always to right
Two white dots always to left
Four black dots always to bottom

Number of dots
1,2,3
2,3,4
3,4,x

x is 5 dots

x corresponding to either answer option 1, 2, 3 or 4.
Following "three white dots is rightmost", position already occupied by white dots, so not 4
Following "Four black dots are bottom", position already occupied by white dots, so not 3
Following "Two white dots always left", position already occupied by white dots, so not 2.

Since black is not white, and always top or bottom, it is 1

1?
shift from white = 270 degrees
shift from black = 90 degrees
add by 2 in the northwest ----> South east direction
>two white dots shit 270 degrees, become four black,
>One black dot shifts 90 degree, becomes three white
>Three white shift 270 degree become five black
Is this right?

The way i was thinking was: black goes counter clockwise to white, white mirrors into second white, second white rotates clockwise into black, repeat pattern. But algorithmically it doesn't make much sense, i think is correct

Oh man, that's a much easier way to determine the correct number of dots. I over complicated it.

Attached: 1587655811036.png (973x408, 109.66K)

1: the pattern is as follows. Same horizontally and vertically
A(x), B (x+1) with rotation in quadrant position, C (x+2) with inversion in quadrant position. The color shifts on the next even integer value. If it isn't option one, then the correct answer wasnt provided in the choices.

The only correct answer is 1
Here is why
>Red square contains a black dot
>cascade SouthEast pattern from BWB
>direct single point implication that Blue boxed in entities must be indicitive of the double wide diagonal down dot fill pattern
>Red square has not enough information to prove this so therefore blue square has the data
>Orange line and mark indicate paralells between boxes with even numbers of light circles
>Pink reaffirms the pattern with odd numbered light circles
>pattern reconstituted through quad dark square indicated by brown line and mark
>Even circles flip position over to other side of quad, shown with two light square in sectors (1,2)-(2,2) and (2,3)-(3,3) if the botton left corner is (0,0) and inclusive of the triple light circle cluster box as (1,1)
>Odd numbers of circles always translate down and over to the left as shown by cyan arrows

Given the above patterns and rules, 1 is the answer since:
>dark green sector quad circles always translate to other side
>dark circles must stay contingent to the diagonal pattern rule runling out 3, 4 and 6
>Circles are always added per diagonal row (orange, pink and brown line) ruling out 3, 4, 5, and 6
>There are no other instances of multiple quadrants within boxes being used for circles ruling out 5 and 6
>when the amount is even, the translation method described with cyan/purple arrows rules out 2
>therefore the only option left is 1

Attached: thepuzzle.png (1946x816, 96.13K)

2, it counts simply 1-2-3-4-5.. + changes side simply top, right, bottom, left etc