How good is Yas Forums at maths/logic?

Wrong. It's 50%.

>Its 2/3 Gogi-bro
hello friend from matushka pidarasia

.5
is wrong, the question states what the probability of the next one. the priori is already given.

Possible scenarios, all equally likely:

Left hand green ball from 1
Right hand green ball from 1
Left hand green ball from 2

Out of these 3, 2/3 are from box 1 with the other ball green and 1 is from box 2 with the other ball red.

Therefore the probability the other ball is green is 2/3.

you're wrong. picking a green ball on the first try favors the chance of you getting a second green ball

Omfg my dude. Read the fucking instructions.

Mid wits always overthinking

1 in 3 (or 33%). Am I surrounded by idiots?

question is phrased such that "odds" start AFTER the first pick (and its a green), so I'm thinking 50%

its not asking the odds of your first pick. this isn't even a reskin of the monty hall problem like your smoothbrain thinks.

I vaguely remember this. It's one of those counterintuitive problems. I think the answer here is 2/3

simplest explanation i have
gg > g > g
gg > g > g
gr > g > r
gr > r > g
rr > r > r
rr > r > r

there's green after green 2 times, and red after green only once so 2/3 is answer

gg > g > g
gg > g > g
gr > g > r

t. actual stats major

dank man
I can't believe stacy abrams was almost your governor

Attached: staceyabrams.jpg (283x178, 6.43K)

you're dumb dude. given that you've picked a green ball, the odds are greater that you pick a second green ball than a red ball.,

50%.
t. never knew math

Kek I misread it, it's 50/50. fpbp once again

gg
gr
1/2
consider rope

50% either it happens or it doesnt. No amount of number crunching changes this simple truth

50% you dumbfuck, that's the easiest fucking question ever.

/thread

33.3% you'd have to pick the box with 2 green balls to get 2 green balls. So you'd only have a 33.3% chance from the start.

EITHER I GET MILLIONAIRE TODAY OR I DON'T. is it 50%?

2/3
I've got an advanced mathematics degree but I'm also stoned so who knows

The green ball is already selected, if from Box A then P of 1.0; if from Box B then P of 0, the green ball can not have been selected from Box C.

Therefore, you have P of 0.5 that the other ball in the box is also green.

t. Liberal arts student

Do you guys have good books or something to improve my maths logic and maths level please ?
I feel like my brain is empty or numb doing this shit

The probability depends on which box you picked it from. The left most 100%, the middle 0%. Idk maybe i'm retarded.

If the first ball was green, that double red box is automatically irrelevant. So it's a 50/50 shot the next ball is either green or red.

if a green ball has been selected, these are the possible outcomes

gg
gg
gr

dumbshit

100%
Because you're all racists who need more multicultural influence so I put more green balls in all the boxes while OP wasn't looking.

50%. Whether those balls are in one, three or six boxes it will still be 50%.

Correct.

There is only one ball left in the box you’ve chosen which is either green or red. If there are only 2 choices then that means 50/50. Midwit.

The double red box doesn't apply any longer because you've already ruled that one out by grabbing a green ball

Apparently an eternity in hell since gambling is a sin

khan academy has course for free

This is conditional probability problem. The probability is 50%. Because you are limited to boxes 1&2 already.

Ranma 1/2

this is correct
how can anyone not know this?