Can Yas Forums into probability? Part 2

Y-you understand probability, right user? How are you going to make it if you can’t even accurately determine your chance of success?


-You are on a game show, and want to win a lambo. There are three doors in front of you, and you may select one of them to open. Behind one is the car; behind the other two are goats.

You choose a door to open. But before opening it, the host opens one of the two doors you didn’t choose- the host, who knows what’s behind each door, will always open a door with a goat.

The host then gives you a choice. Do you want to stay with the original door you selected, or switch to the second unopened door? What will give you the best chance of winning the car? Do you stay, switch, or does it not matter?

Attached: 330D3DD3-A126-4C76-B4F5-A44043348E73.png (1200x667, 55.44K)

Other urls found in this thread:

en.wikipedia.org/wiki/Monty_Hall_problem
youtube.com/watch?v=TVq2ivVpZgQ
twitter.com/SFWRedditVideos

This is a well known conditional probability problem. Switching is the right answer (2/3 chance)

this question is such a meme by now, even people who dont understand probability know the correct answer

It's 50/50 because it states you already have a green ball so we start calculating from that point.

It does not matter

Please guys, OP even used the picture from the wikipedia article en.wikipedia.org/wiki/Monty_Hall_problem

I don't agree

>This is a well known conditional probability problem. Switching is the right answer (2/3 chance)

This
and it’s obvious OP now fuck off back to rebbit fag

You Punch out the host, kick in both doors, and wheel out in the Lambo getting dome from the stage model.

Chad gang

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>-you understand probability, right user?
No I don't