Can Yas Forums into probability?

Incorrect.

You have already picked a box
You have already selected a ball
That ball is green
One ball remains inside the box

That ball within the box is either red or green.

50%

Both boxes are isolated instances.
if you select 1 box and pull out a green ball, It is guaranteed that the next ball will be either green or red.
there is no question about it. the 3 box situation is a red herring.
you reduced the equation to a [1,0] and [0/0] and pulled out a 0.
therefore you either only have the choice of a 1 or a 0 to choose from, a 50% chance.

Is this Yas Forums humor??

Absolutely diminutive intelligence. 110 is my guess.

>so there is no reason to separate the balls in box one
Indeed.

But think of it this way :

You have 6 easter eggs. Inside of them is a piece of paper with a number written in it.

There is 3 green easter eggs, 3 red easter egg.
2 green easter egg have written "Box 1" written in it.
1 green easter egg and 1 red easter egg have written "Box 2"
2 red easter egg have written "Box 3"

You pick a random green easter egg.

What is the probability "Box1" is written inside ?

You picked a green ball. 2 out of 3 possible green balls have another green ball as their neighbor.

Read here: It becomes easier to comprehend if you expand the scale of the numbers

You will never convince me that it isn't 50%.

If choice 1 was a green ball, the double red ball option CEASES to exist in the equation. You either have the double green or 1 green 1 red.

It is more probably that the green ball in your hand game from box 1.

observed probability vs actual probability

>You either have the double green or 1 green 1 red.

Yes, and there is a 2/3rds chance that you have the double green box.

The green ball in your hand is one of 3 possible green balls. 2 of those possible green balls have another green ball as their neighbor.

But it's not a 1/3rd chance. I have to options in the next step. Green or red. That is 50-50.