How good is int at maths/logic?
How good is int at maths/logic?
Josiah Smith
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Adrian Baker
66.6...%
Levi Lopez
1/3
Jace Baker
no wait, it's 50%
Levi Reed
This because it excludes the red balls only box
/thread
Landon Nguyen
1/2
Aaron Gonzalez
2/3
Dylan Hill
I don't want to answer. Thanks.,
Brayden Reed
Bumperino
Elijah Bailey
My calculations suggest that the probability is 33.33%, repeating, of course.
[code]
var boxes = [
['green', 'green'],
['green', 'red'],
['red', 'red']
];
var positiveOutcomes = 0;
var totalOutcomes = 0;
for (var i=0; i
Robert Clark
56%
Nathan Campbell
2/3
Luis Morales
uhhhmmmm 56%???
Eli Scott
40%
Nicholas Powell
3.1416
Parker Ortiz
retard
You're just testing whether it selected the box with 2 green balls, the image shows it's assumed you already selected a green ball.
var boxes = [
['green', 'green'],
['green', 'red'],
['red', 'red']
];
var positiveOutcomes = 0;
var totalOutcomes = 0;
for (var i=0; i
Isaiah Martin
0.148137
nice try
Isaac Turner
Jason Reed
It's simple, 2/3
Jaxon Perry
the double green box has 2 `true' cases
Owen Cox
java is a disgusting language and you should feel bad
t. rustchad
Eli Hill
Doesn't matter, I always make any ball blue
Jack Jones
Nah. You only eliminate one box totally, but the rest of the boxes aren't equal. It's twice as likely to pick a green ball from the wholly green box, so the likelihood that the other ball is also green is also double.
John Carter
0.01%
Jaxon Campbell
It is not that complicated.
Cameron Wright
Lmao the Israeli deleted his post
Bentley Gonzalez
hehe
Evan Torres
Anthony Ramirez
I am colorblind so I cannot see the boxes
Brayden Brooks
There used to be a version with gold and silver balls which this explanation is based on but it's the same problem.
It's 2/3.
James Wilson
Use Bayes' theorem. Let A=1st ball is green, B=2nd ball is green, then
P(A|B)=P(B|A)P(A)/P(B)
P(A)=1/3(1+1/2), P(B)=1/3, P(A|B)=1 so
P(B|A)=(1x1/3)/(1/3(3/2))=2/3.
Adrian Nelson
13% chance that it will be 50% green balls
Asher Morales
>have 2 possible boxes
>1 has a red ball and 1 has a green ball
>1/2 of the balls are green
>1/2 is 50%
>some retard did all that math and got 2/3 instead
I fucking hate french people
Mason Collins
With only the information that you've picked a green ball, it's twice as likely that you're taking from the two green ball box than the one with a green and a red. On average, two out of every three green balls you pick will be from the two green ball box.
Adrian Lewis
50%
Either the ball is green or it isn't
Evan Nelson
The fact that there's two possibilities doesn't mean that they're equally likely
John Garcia
It's almost as if probabilities aren't as intuitive as you'd think they are.